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-1/4x^2+30=0
Domain of the equation: 4x^2!=0We multiply all the terms by the denominator
x^2!=0/4
x^2!=√0
x!=0
x∈R
30*4x^2-1=0
Wy multiply elements
120x^2-1=0
a = 120; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·120·(-1)
Δ = 480
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{480}=\sqrt{16*30}=\sqrt{16}*\sqrt{30}=4\sqrt{30}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{30}}{2*120}=\frac{0-4\sqrt{30}}{240} =-\frac{4\sqrt{30}}{240} =-\frac{\sqrt{30}}{60} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{30}}{2*120}=\frac{0+4\sqrt{30}}{240} =\frac{4\sqrt{30}}{240} =\frac{\sqrt{30}}{60} $
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